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Pie
3 years ago
9

Anyone know what -36 divide by 4 is i forgot lol

Mathematics
2 answers:
qwelly [4]3 years ago
7 0
-9 because you go to a Calculator and you can solve it
notka56 [123]3 years ago
6 0
The answer is gonna be -9
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Consider the following pair of equations:
nlexa [21]
Since both of the equations equal Y can substitute one for the Y and say that
X-1=3x+3
-4=2x
-2=x
7 0
3 years ago
There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
This season, the probability that the Yankees will win a game is 0.49 and the probability that the Yankees will score 5 or more
yanalaym [24]

Answer:

0.226 = 22.6% probability that the Yankees will lose when they score 5 or more runs

Step-by-step explanation:

Conditional probability:

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

If the Yankees score 5 or more runs, either they win, or they lose. The sum of these probabilities is 1.

Probability that the Yankees win:

Event A: Scoring 5 or more runs.

Event B: Winning

The probability that the Yankees will score 5 or more runs in a game is 0.53.

This means that

The probability that the Yankees win and score 5 or more runs is 0.41.

This means that

So

0.774 probability that the Yankees will win when they score 5 or more runs

What is the probability that the Yankees will lose when they score 5 or more runs?

p + 0.774 = 1

p = 1 - 0.774

p = 0.226

0.226 = 22.6% probability that the Yankees will lose when they score 5 or more runs

4 0
3 years ago
What number can go into 2470,121 and 45<br>​
Usimov [2.4K]

Answer:

Step-by-step explanation:

All of these numbers can be divided by 2, 3, 5, 7, 11, 13...

There is no whole number if you want to divide each number.

121 only goes into 1, 11, and 121. No other numbers have 11

45/2 = 22.5

45/3 = 15

45/5 = 9

2470/2 = 1235

2470/3 = 823.33333...

2470/5 = 494

121/2 = 60.5

121/3 = 40.33333...

121/5 = 24.2

4 0
3 years ago
The product of a number and its blank is one
Monica [59]

The product of any number and its reciprocal is ' 1 '.

Call the number  ' Q '.
Whatever the number is, its reciprocal is  1/Q .

Their product is 
                             ( Q ) x ( 1/Q )  =  ( Q/Q )  =  1
5 0
3 years ago
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