Answer:
In C:
#include <stdio.h>
#include <math.h>
int main(){
float f0,r,temp;
r = pow(2.0,1.0/12);
printf("f0: "); scanf("%f", &f0);
temp = f0;
for(int i = 0; i<=4;i++){
f0 = f0 * pow(r,i);
printf("%.2lf ", f0);
f0 = temp; }
return 0;
}
Explanation:
This declares f0, r and temp as float
float f0,r,temp;
This initializes r to 2^(1/12)
r = pow(2.0,1.0/12);
This prompts the user for f0
printf("f0: "); scanf("%f", &f0);
This saves f0 in temp
temp = f0;
This iterates the number of keys from 0 to 4
for(int i = 0; i<=4;i++){
This calculates each key
f0 = f0 * pow(r,i);
This prints the key
printf("%.2lf ", f0);
This gets the initial value of f0
f0 = temp; }
return 0;
Answer:
oneMore(oneMore(oneMore(oneMore(oneMore(0)))))
Explanation:
- As a function has been explained which when given an integer results as a next integer. oneMore(given-integer)= next integer
- As we are restricted to use 0 only and can't use operators like + - * /.
- We have to obtain a value 5
- So doing step-by-step:
(oneMore(0))=1
(oneMore(oneMore(0)))=2
(oneMore(oneMore(oneMore(0))))=3
(oneMore(oneMore(oneMore(oneMore(0)))))=4
oneMore(oneMore(oneMore(oneMore(oneMore(0)))))=5
Answer:
Context-sensitive language is a subset of context-free language
Explanation:
Considering the available options, the statement that is considered wrong is "Context-sensitive language is a subset of context-free language."
This is because generally every regular language can be produced through the means of context-free grammar, while context-free language can be produced through the means of context-sensitive grammar, and at the same time, context-sensitive grammars are produced through the means of Recursively innumerable.
Hence, the correct answer in this correct answer to the question is the last option *Context-sensitive language is a subset of context-free langage
