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MArishka [77]
3 years ago
6

Monique makes $11 per hour delivering pizzas. Monique works Monday

Mathematics
1 answer:
Ilya [14]3 years ago
8 0

Answer:

x > 39 hours

Step-by-step explanation:

Let x be the number of hours she worked.

11x - is how much she would get paid for working for x hours

11x + 20 > 450

11x > 430

x > 39 hours

Hope that helped!!! k

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Half the perimeter of a harden is 18 feet. The garden is 8 feet longer than it Is wide. How wide is the garden?
MatroZZZ [7]
The answer to this question is 10 feet wide
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Answer: First you need to calm down my man. a. 12. b 15 c. 9

2 1/2 hours

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Marsh trail is 2 5/10 or 2 1/2 miles longer than Woodland Trail

Step-by-step explanation: Question 3. a. Common Denominator is 12 b. Common Denominator is 15 c. Common denominator is 9. Question 4 It will take 2 and 1/2 hours to complete all of his tasks. Question 5. 2 9/12 + 2 2/12 Question 2. Marsh Trail is 2 5/10 and 2 1/2 miles longer than Woodland Trail. Hope this helps and stay calm.

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You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

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