All categories

3 years ago

Three times four, plus two to the third power

Mathematics

2 answers:

Nadya [2.5K]3 years ago

8 0

It is 20.because 3×4+2cubed is 20
^
=12 ^
2×2×2=8 so 8+12=20

Tomtit [17]3 years ago

5 0

You have to use bodmas
so 3x4+2cubed basically means
3x4+2x2x2
so do all the multiplication first
3x4=12
2x2x2=8
so 12+8=20

You might be interested in

To find 61 × 1,000, annex ______ zeros to _____ to form the product _______

NARA [144]

The answer is 61,000

8 0

3 years ago

Mia spent 30 minutes answering the math questions on the exam. This was Three-fifths of the total amount of time allotted for th

soldier1979 [14.2K]

Answer:

x×3/5=30

3x/5=30

3x=5×30

3x=150

x=150/3

x=50

4 0

2 years ago

The two lines represent the amount of water, over time in two tanks that are the same size. Which container is filling more slow

Brut [27]

B is slowly and A is filling more quickly because the amount of water increases during a smaller period of time.

6 0

3 years ago

Subtract. (29v)−(−13v+59)

lbvjy [14]

Answer:

(29v)−(−13v+59)

29v + 13v - 59

42v -59

5 0

2 years ago

Read 2 more answers

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago