This is a horizontal line at y = -3. If you want to find it mathematically, you could find the slope (y2-y1)/(x2-x1) and you would get 0 over 5, so you know the slope is zero. Pick either point and substitute the numbers into point-slope formula. I went with (3, -3) and got (y - -3) = 0(x-3). The right side is just 0, and if you subtract three from both sides to isolate y, you get the equation y = -3.

3 0

3 years ago

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Find the nth term 1, 5, 9. 13, 17

mojhsa [17]

a1 = 1 and d = 4

a(n) = a1 + d(n - 1)

a(n) = 1 + 4(n - 1)

8 0

3 years ago

Find the value of X or Y so that the line through the points has the given slope. (X, 0) and (4,1); slope: 1/5

Ronch [10]

Point slope formula:
(y₂ -y₁) = m(x₂ - x₁)
(1 - 0) = $\frac{1}{5}$ (4 - X)
1 = $\frac{4}{5} - \frac{1}{5} X$
$\frac{1}{5} = -\frac{1}{5} X$

-1 = X

8 0

3 years ago