The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are 
<h3>How to determine the possible zeros?</h3>
The function is given as:
f(x) = 3x^6 + 4x^3 -2x^2 + 4
The leading coefficient of the function is:
p = 3
The constant term is
q = 4
Take the factors of the above terms
p = 1 and 3
q = 1, 2 and 4
The possible zeros are then calculated as:
So, we have:
Expand
Solve
Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are
Read more about rational root theorem at:
brainly.com/question/9353378
#SPJ1
The sequence is ×2.
12,288 is the 12th term.
24,570 is the answer. It is the sum.
It would be 10.87 because there is 16oz in a pound so 29/16= 1.8125 so 1.8125= 10.875
Hope this helps
Have a great day/night
If length is x, then width is 6+x
<span>Perimeter = 2*(x + 6+x) = 52 </span>
<span>2*6 + 2*2x = 52 </span>
<span>4x = 52 - 12 = 40 </span>
<span>x = 40/4 = 10 </span>
<span>Area = length*width = 10*(6+10) </span>
<span>Area = 10*16 = 160 meter square</span>
Answer: 3
Step-by-step explanation:
