The solution would
be like this for this specific problem:
ab/a+b = c
b = -1 + a
for c:
<span>(5(-1 + 5))/(5 + (-1 +5))
</span><span>5(4)/ 5 + 4
</span><span>20 / 9
</span>
<span>The correct
answer between all the choices given is the first choice or letter A. I am
hoping that this answer has satisfied your query and it will be able to help
you in your endeavor, and if you would like, feel free to ask another question.</span>
Answer:
In summary, an inscribed figure is a shape drawn inside another shape. A circumscribed figure is a shape drawn outside another shape. For a polygon to be inscribed inside a circle, all of its corners, also known as vertices, must touch the circle.
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
f(x) = 5x^3 +1, g(x) = – 2x^2, and h(x) = - 4x^2 – 2x +5
f(-8) = 5(-8)^3 +1 = 5 *(-512) +1 =-2560+1 =-2559
g( -6) = -2 ( -6) ^2 = -2 ( 36) = -72
h(9) = -4( 9)^2 -2(9) +5 = -4 ( 81) -18+5 = -324-18+5=-337
<h2> The answer is very simple add the whole numbers then find the LCM of 3 and 4 which is 12 then multiply 3/4 by 3 which will be 9/12 then multiply 2/3 by 4 which will be 9/12 then we add 9/12 + 8/12 which will equal to 5 17/12 which we can reduce and answer will be 6 5/12 spinach.</h2>
Answer:
The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)
Step-by-step explanation:
We have the following expression
Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.
Now we search that values of x make 0 the denominator factoring the polynomial 
We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.
These numbers are -2 and 1
Then the factors are:
We do the same with the numerator
We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.
These numbers are 3 and 1
Then the factors are:
Therefore
Note that 
only if 
So since 
is not included in the domain the function has a discontinuity in
