The answer is 2x-8 and 1/7+7
Answer:
B
Step-by-step explanation:
6+6+10+10+15+15
We have:
Initial velocity (u) = 32 m/s
Final velocity (v) = 0 m/s ⇒ The value is zero because the car comes to stationary position when it stops
Time = 14 seconds
We can use one of the constant acceleration equation:

where

is the acceleration



The acceleration is 2.3 m/s⁻² and the negative sign shows deceleration
Answer:
32.5
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