1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kompoz [17]
3 years ago
8

I need help asap please thank you

Mathematics
2 answers:
worty [1.4K]3 years ago
4 0

Answer:

370

Step-by-step explanation:

Every time, the number adds 7. 66*7 will be 462.

-92+462 is 370

g100num [7]3 years ago
4 0

Answer:

Step-by-step explanation:

1 term = -92

Common difference = -1

Desired term = 2 ( I guess?)

- 92 -1 ( 2 - 1)

-93 × -1

-94

You might be interested in
What is the completely factored form of f(x)=x^3-7x^2+2x+4
xxMikexx [17]

Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)

Steps:

x^3-7x^2+2x+4

Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}

\frac{x^3-7x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}

\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4

\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

8 0
3 years ago
How do I do this????
statuscvo [17]
3,107\div 350\approx8.9

So she need at least 9 cans.
5 0
3 years ago
Read 2 more answers
Find the values of x and y for which the quadrilateral below must be a parallelogram.
Fofino [41]
Since there is no picture, find here-under the conditions that a quadrilateral becomes a parallelogram:
( All are either or)
1- opposite sides should be congruent
2- opposite angles should be congruent
3- opposite sides parallel
4-The sum of 2 adjacent angles to equal 180°
5 the 2 diagonals intersect in their middle

With any of these conditions, if confirmed, you can conclude that the quadrilateral is a parallelogram (By the way a rectangle is a parallelogram with one angle =90°

5 0
3 years ago
Read 2 more answers
PLEASE HELP WITH #18 DUE SOON
AlexFokin [52]
Not sure what them other words mean I haven’t done this in a minute but the corresponding angles are all the same but the size is difference
3 0
3 years ago
Read 2 more answers
Which expression is equivalent to sqrt8x^7y^8? assume x>0
Ilia_Sergeevich [38]

Answer:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

Step-by-step explanation:

Given

\sqrt{8x^7y^8

Required

Evaluate

\sqrt{8x^7y^8

Separate each factor with multiplication sign

\sqrt{8*x^7*y^8

Express 8 as 4 * 2 and x^7 as x^6 * x

\sqrt{4 * 2 *x^6 * x*y^8

Split each factor

\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Evaluate \sqrt4

2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Apply law of indices:

2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}

2 * \sqrt{2} * x^3 * \sqrt{x} * y^4

Reorder

2* x^3 * y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2*x}

2x^3y^4 * \sqrt{2x}

2x^3y^4 \sqrt {2x

Hence:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the length of this line? 30 POINTS!!
    6·2 answers
  • What is a multiplication equation that has a solution of 2/7
    14·1 answer
  • 7x(2x blank)=42 plz answer fast will mark as branliest!!!
    6·1 answer
  • A worker is handling the four of a rectangle room that is 12 feet by 15 feet.The tiles are square with side lengths 1 1/3 feet.
    10·1 answer
  • A researcher reports an F-ratio with df = 1, 24 for an independent-measures experiment. If all the treatments had the same numbe
    9·1 answer
  • What is the missing length?
    5·2 answers
  • What is the slope-intercept form of the following equation?
    15·1 answer
  • Translate the sentence into an inequality.
    9·2 answers
  • Pls help I’m so confused
    5·1 answer
  • I HAVE ANOTHER QUESTION PLEASE HELP
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!