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Papessa [141]
3 years ago
14

Plot another sin function of 20% higher frequency over the same range.

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Step-by-step explanation:

The frequency of sine function is given by the number of periods in a given range. For example:

  • Frequency for sin(x) is 1 in the interval [0,2\pi].

This means that, if we want another sine function with frequency 20% higher, we need that function to have a frequency of 1.2 in the interval [0,2\pi].

To be easier to see we will consider interval [0,10\pi] instead of [0,2\pi]. In this interval sin(x) has 5 periods, therefore our new sine function should have 6 periods.

Finally, as we can see in the graph, the function sin(\frac{6}{5}x ) (in blue) has a frequency 20% higher than sin(x) (in red). This can be easily seen counting the number of periods between 0 and 10\pi for both functions. 5 for sin(x) and 6 for sin(\frac{6}{5} x).

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Answer:

y = 4x - 5

Step-by-step explanation:

Use the point slope form and add in the ordered pairs \frac{3 + 1}{2 - 1} , and once you solve this it equals \frac{4}{1}, or just 4. Now you have the first part of your equation, y = mx + b, but now you have y = 4x + b. To find b, substitute the x and y values of one of the given ordered pairs in for x and y in the equation, and I am using (2,3). The equation now looks like this: 3 = 4(2) + b. Now solve: 3 = 8 + b

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A quadrilateral has angles that measure 101°, 133°, and 76°.
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Ribbon A is 1/3 m long. It is 2/5 m shorter than Ribbon B. What's the total length of the two ribbons?
Softa [21]

Hi

Answer:

\frac{11}{15}

Step-by-step explanation:

A = \frac{1}{3}

B = \frac{2}{5}

_

A = \frac{1x5}{3x5}=\frac{5}{15}

B = \frac{2x3}{5x3}=\frac{6}{15}

\frac{5}{15} + \frac{6}{15} = \frac{11}{15}

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Good Luck!

#Turkey

5 0
4 years ago
Read 2 more answers
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