Why do we need to integrate probabilities in statistics?

1 answer:

5 0

For the answer to the question above asking why do we need to integrate probabilities in statistics?
Well, integration is used very very often in theoretical statistics. Transformation relates to the result that data values that are modelled as being random variables from any given continuous distribution can be converted to random variables having a standard uniform distribution. So, we need to see other possibilities by combining (one thing) with another.

You might be interested in

Which of the following is the most appropriate unit to describe the rate at which people are entering a theme park?

ad-work [718]

The correct answer is:

d) People per hour, because the dependent quantity is the people

Explanation:

In this situation, the two quantities are people and hours. These are the two things in this problem we can count or measure.

The independent variable is the one that causes a change, while the dependent variable is the one that gets changed. In this situation, the number of people change every hour; this means the number of people gets changed, which makes it the dependent variable. This means that the independent variable must be time.

Since people is dependent and time is independent, "people per hour" would be the best form of this statement.

6 0

3 years ago

26 - (2c + 4) = 2(C+6) +C what is c

Zigmanuir [339]

Answer:

c = 2

Step-by-step explanation:

26 - (2c + 4) = 2(c+6) + c

26 - 2c + 4 = 2c + 12 + c

26 - 4 - 12 = 2c + 2c + c

10 = 5c

2 = c

6 0

3 years ago

Read 2 more answers

Rewrite as a simplified fraction 1.6 <-- repeating=?

Norma-Jean [14]

$1.6666...=1.\overline{6}=1.(6)\\\\x=1.6666...\ \ \ |multiply\ both\ sides\ by\ 10\\10x=16.6666...\\\\10x-x=16.6666...-1.6666...\\9x=15\ \ \ \ |divide\ both\ sides\ by\ 9\\\\x=\frac{15}{9}\\\\\boxed{x=1\frac{6}{9}}\\\\simplify\\\\x=1\frac{6:3}{9:3}=\boxed{1\frac{2}{3}}$