3 years ago

Find the percent of change of 37 is decreased to 17.

Mathematics

1 answer:

Anettt [7]3 years ago

7 0

54.0541% is the answer.

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According to the fundamental theorem of algebra which polynomial function has exactly 8 roots? A.F(x)=(3x^2-4x-5)(2x^6-5) B.f(x)

choli [55]

I think it’s a because I added from the therum

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3 years ago

You supervise the feeding of dogs at a kennel you use an average of 10 1/2 pounds of dog food each day.at the rate how many poun

liq [111]

Answer:

73.5 pounds of dog food in 7 days

Step-by-step explanation:

10 1/2 x 7

10x 7 =70

1/2 x 7 = 3.5

70 + 3.5 =73.5 pounds of dog food in 7 days

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2 years ago

A neon light flashes five times every 10 seconds. Show that the light flashes 43 200 times in one day.

11Alexandr11 [23.1K]

1 day = 24 hours

1 hour = 60 minutes

1 minute = 60 seconds

60 seconds x 60 minutes = 3,600 seconds per hour

3,600 seconds per hour x 24 hours = 86,400 seconds per day.

The light flashes 5 times every 10 seconds:

5 flashes / 10 seconds = 1 flash every 2 seconds

86,400 seconds / 2 seconds = 43,200 flashes per day.

4 0

2 years ago

Use elimination to solve the system of equations. Show your work 5×-3y=6,2×+5y=-10.

Fofino [41]

Answer:

5(5x-3y=6)

3(2x+5y=-10)

25x-15y=30

6x+15y=-30

31x= 0

x = 0

5(0)-3y=6

-3y=6

y= -2

(0,-2)

6 0

3 years ago

Read 2 more answers

Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0

erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

$15x^2-kx+1=0$ (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

$2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8$

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

$15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}$

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0

3 years ago