Answer:
10 terms
Step-by-step explanation:
equate the sum formula to 55 and solve for n
n(n + 1) = 55 ( multiply both sides by 2 to clear the fraction )
n(n + 1) = 110 ← distribute parenthesis on left side
n² + n = 110 ( subtract 110 from both sides )
n² + n - 110 = 0 ← in standard form
Consider the factors of the constant term (- 110) which sum to give the coefficient of the n- term (+ 1)
the factors are + 11 and - 10 , since
11 × - 10 = - 110 and 11 - 10 = + 1 , then
(n + 11)(n - 10) = 0 ← in factored form
equate each factor to zero and solve for n
n + 11 = 0 ⇒ n = - 11
n - 10 = 0 ⇒ n = 10
However, n > 0 , then n = 10
number of terms which sum to 55 is 10
Answer: True, False, False, False, False
<u>Step-by-step explanation:</u>
a) 5x - 7(x - 1)
5x - 7x + 7
-2x + 7 ⇒ a = -2, b = 7 <em>One Solution</em>
b) 3(x - 5) - 7
3x - 15 - 7
3x - 22 ⇒ a = 3, b = -22 <em>One Solution</em>
c) 2 - 7x + 3 + 4x
4x - 7x + 3 + 2
-3x + 5 ⇒ a = -3, b = 5 <em>One Solution</em>
d) -3(x - 3) - 1
-3x + 9 - 1
-3x + 8 ⇒ a = -3, b = 8 <em>One Solution</em>
e) -5x + 2 + 2x + 4
-5x + 2x + 2 + 4
-3x + 6 ⇒ a = -3, b = 6 <em>One Solution</em>
Your answer is B Hope I helped :)
Answer:
8 times larger
Step-by-step explanation:
(15+10) is the singular equation alone. Muiltiply it by 8, and it's 8 times larger then the initial singular expression. Therefore, the answer is 8 times larger.
