Answer:
2^12
Step-by-step explanation:
16^3 can be rewritten as (2^4)^3 which can then be rewritten as 2^12 by multiplying the exponents
Answer:
Raising something to a negative exponent is just taking the reciprocal of the amount.
Step-by-step explanation:
Let's assume that you wanted to know what
is.
To find it, you would take the reciprocal of the x amount. So
becomes
.
This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So
would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase
to
, you would have to multiply a with
two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease
to
, you would have to divide
by a 3 times.
If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times:
means that you are dividing 1 by a 3 times.
Hope this helps.
The values of x are -22 and -2 and there are not extraneous solutions
<h3>How to solve the equation?</h3>
The equation is given as:
2|x + 7|= x - 8
Expand the absolute bracket
|2x + 14|= x - 8
Remove the absolute bracket
2x + 14 = x - 8 and 2x + 14 = -x + 8
Evaluate the like terms
x = -22 and 3x = -6
This gives
x = -22 and x = -2
Hence, the values of x are -22 and -2 and there are not extraneous solutions
Read more about absolute value expressions at:
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<u>EXPLANATION</u><u>:</u>
Given that
sin θ = 1/2
We know that
sin 3θ = 3 sin θ - 4 sin³ θ
⇛sin 3θ = 3(1/2)-4(1/2)³
⇛sin 3θ = (3/2)-4(1/8)
⇛sin 3θ = (3/2)-(4/8)
⇛sin 3θ = (3/2)-(1/2)
⇛sin 3θ = (3-1)/2
⇛sin 3θ = 2/2
⇛sin 3θ = 1
and
cos 2θ = cos² θ - sin² θ
⇛cos 2θ = 1 - sin² θ - sin² θ
⇛cos 2θ = 1 - 2 sin² θ
Now,
cos 2θ = 1-2(1/2)²
⇛cos 2θ = 1-2(1/4)
⇛cos 2θ = 1-(2/4)
⇛cos 2θ = 1-(1/2)
⇛cos 2θ = (2-1)/2
⇛cos 2θ = 1/2
Now,
The value of sin 3θ /(1+cos 2θ
⇛1/{1+(1/2)}
⇛1/{(2+1)/2}
⇛1/(3/2)
⇛1×(2/3)
⇛(1×2)/3
⇛2/3
<u>Answer</u> : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.
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