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Nataly [62]
2 years ago
5

1

Mathematics
1 answer:
cricket20 [7]2 years ago
3 0

Answer:

<em>5.33 secs</em>

Step-by-step explanation:

Given the equation of the height modeled by the equation/

h(t) = -3.2 + 12.5t + 24.8

The object strikes the ground when the height h(t) is zero

Substituting h(t) = 0 into the expression

h(t) = -3.2t² + 12.5t + 24.8

0 =  -3.2t² + 12.5t + 24.8

-3.2t² + 12.5t + 24.8 = 0

Multiply through by minus sign

3.2t² - 12.5t - 24.8 = 0

From the expression a = 3.2, b = -12.5 and c = -24.8

t = -(-12.5)±√(-12.5)²-4(3.2)(-24.8)/2(3.2)

t = 12.5±√156.25+317.44)/6.4

t = 12.5±√473.69/6.42

t = 12.5±21.76/6.42

t = 12.5+21.76/6.42

t = 34.26/6.42

t = 5.33secs

<em>Hence the object strike the ground after 5.33 secs</em>

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