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3 years ago

0.02 write as a fraction or mixed number in simplest form

Mathematics

2 answers:

zmey [24]3 years ago

7 0

I think as a fraction it would 2 over one hundred

Iteru [2.4K]3 years ago

5 0

0.02 is as a fraction= 200/1000
but I'm really sorry I'm not sure about the mixed number one so I won't mislead you and just put a random guess

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3) gentry is training for a marathon. she increases the amount of time she runs by 5 mins. each day to build up her endurance. o

nika2105 [10]

Y=5x+30

X is the days

And so by plugging in x you get

y=5(5)+30
y=25+30
y=55

And so by day 5 she's running 55 minutes

But that's what I think

3 0

3 years ago

Thanks an advance~! Show your work :)

Talja [164]

Only AAS cannot prove this.

So the answer will be A.

6 0

3 years ago

Question :

Darya [45]

Answer:

1156

Step-by-step explanation:

We know that,

( a + b ) ² = a² + 2ab + b²

We can follow the same method to find the value of this.

12² + 22²

( 12 + 22 ) ²

12² + 2 × 12 × 22 + 22²

144 + 24 × 22 + 484

144 + 528 + 484

672 + 484

Let me know if you have any other questions. :)

6 0

2 years ago

Consider the equation below.

Marta_Voda [28]

Be because I did this it’s just extremely hard to explain how to trust OK open helps

7 0

2 years ago

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

8 0

3 years ago