Answer:
For Lin's answer
Step-by-step explanation:
When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.
Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.
Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
![g(h(x)) = \sqrt[4]{x^2 + x +5} + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%20%2B%20x%20%2B5%7D%20%2B%203)
b
![h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%20%3D%20%5Csqrt%7Bx%7D%20%20%2B%207%5Csqrt%5B4%5D%7Bx%7D%20%2B%2017)
c
![h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10](https://tex.z-dn.net/?f=h%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E2%20%2B%20x%5E2%20%2B%20x%20%2B%2010)
Step-by-step explanation:
From the question we are told that
and
![g(x) = \sqrt[4]{x} + 3](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B4%5D%7Bx%7D%20%2B%203)
Considering first question
Now we are told g(h(x))
i.e
![g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203)
=>
Considering second question
Now we are told h(g(x))
i.e
![h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%3D%20%20%5Bx%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203%5D%5E2%20%2B%20%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203%20%2B%205)
=> 
=> 
=>
Considering third question
![h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5](https://tex.z-dn.net/?f=h%28h%28x%29%29%3D%20%5Bx%5E2%20%2B%20x%20%2B%205%5D%5E2%20%2B%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%20%2B%20%205)
=>
Hello,
ρ=√(4²+3²)=5
tan θ=-3/-4=3/7
==>θ=216,869897...° (since θ is in the III quadrant)≈216.9°
Answer C
<span>1/6, 2/12, 3/18, 4/24, 5/30, 6/36, 7/42, 8/48, 9/54, 10/60, and so on</span>
Answer:
the first one
Step-by-step explanation:
they meet on (-3,-$4) so just plug the numbers in
