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andre [41]
3 years ago
6

0.02 write as a fraction or mixed number in simplest form

Mathematics
2 answers:
zmey [24]3 years ago
7 0
I think as a fraction it would 2 over one hundred
Iteru [2.4K]3 years ago
5 0
0.02 is as a fraction= 200/1000
but I'm really sorry I'm not sure about the mixed number one so I won't mislead you and just put a random guess
You might be interested in
3) gentry is training for a marathon. she increases the amount of time she runs by 5 mins. each day to build up her endurance. o
nika2105 [10]
Y=5x+30

X is the days

And so by plugging in x you get

y=5(5)+30
y=25+30
y=55

And so by day 5 she's running 55 minutes

But that's what I think
3 0
3 years ago
Thanks an advance~! Show your work :)
Talja [164]
Only AAS cannot prove this. 

So the answer will be A.
6 0
3 years ago
Question :
Darya [45]

Answer:

1156

Step-by-step explanation:

We know that,

( a + b ) ² =  a² + 2ab + b²

We can follow the same method to find the value of this.

12² + 22²

( 12 + 22 ) ²

12² + 2 × 12 × 22 + 22²

144 + 24 × 22 + 484

144 + 528 + 484

672 + 484

<u>1156</u>

Let me know if you have any other questions. :)

6 0
2 years ago
Consider the equation below.
Marta_Voda [28]
Be because I did this it’s just extremely hard to explain how to trust OK open helps
7 0
2 years ago
How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98
Irina18 [472]

Answer:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=1400 represent the sample standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be z_{\alpha/2}=2.33, replacing into formula (b) we got:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

8 0
3 years ago
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