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Ivenika [448]
3 years ago
10

Find the value of S for an infinite geometric series with r= 1/6 and a1=10

Mathematics
1 answer:
Lelu [443]3 years ago
5 0
S=a1/1-r=10 x 6/5 = 12
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Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN
sashaice [31]

Answer:

The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

 and (x2 , y2) are x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

 N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}

∵ y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}

∴ The coordinates of the midpoint are (-2\frac{1}{2},4\frac{1}{2})

* The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

8 0
3 years ago
Help me with this math problems please only the ones that are circled​
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5 0
3 years ago
Solve for x: X^2 = 4/16
Rainbow [258]

We know that

x = \sqrt{\frac{4}{16}}

So:

x = \frac{2}{4}

6 0
3 years ago
Which digit is in the tenths place 314.902
ololo11 [35]
Nine is in the tenths place

4 0
3 years ago
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A system of equations is shown. y = 3x - 2;. y = x^2. What are the solutions to the system of equations?
Taya2010 [7]

Answer: the solutions to the system of equations are x = 2 and x = 1

Step-by-step explanation:

The system of equations given equation is

y = 3x - 2 - - - - - - - - - - 1

y = x^2 - - - - - - - - - - - - 2

Substituting 1 into equation 2, it becomes

x^2 = 3x - 2

x^2 - 3x + 2 = 0

We would apply the method of factorization in solving the equation. We will get two numbers such that when added, the result would be - 3x and when multiplied, the result would be 2x^2. The numbers are - 2x and - x. It becomes

x^2 - 2x - x + 2 = 0

x(x - 2) - 1(x - 2) = 0

(x - 2)(x - 1) = 0

x - 2 = 0 or x - 1 = 0

x = 2 or x = 1

.

7 0
3 years ago
Read 2 more answers
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