Find the value of S for an infinite geometric series with r= 1/6 and a1=10

HELP HELP HELP

mojhsa [17]

Answer:

2998 ; 17%

Step-by-step explanation:

Given the function:

t(c)=-3970.9(ln c)

c = % of carbon remaining ; t = time

1.) c = 47% = 47/100 = 0.47

t(0.47) = - 3970.9(In 0.47)

t = - 3970.9 * −0.755022

t = 2998.119

t = 2998

B.)

t = 7000

t(c)=-3970.9(ln c)

7000 = - 3970.9(In c)

7000 / - 3970.9 = In c

−1.762824 = In c

c = exp(−1.762824)

c = 0.1715596

c = 0.1715596 * 100%

c = 17.156% ; c = 17%

8 0

3 years ago

Read 2 more answers

On a given planet, the weight of an object varies directly with the mass of the object. Suppose that an object whose mass is 9 k

nadya68 [22]

Answer:

6 kg

Step-by-step explanation:

Given is weight of an object directly varies with the mass of the object .

Let the constant of proportionality be k

So,

Weight = K×(mass of the object)

For an object , weight = 45 N

mass = 9 kg

So , 45 = K×9

K = 5.

Now, for the other object ,

Weight = 30 N. K = 5 (as obtained above)

So, 30 = 5×(mass of the object)

mass of the object = 6 kg.

5 0

3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

so

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago

Can somebody please help me with the question below and please explain how to find the answer? plz, I'm studying for a test plzz

blagie [28]

Answer:

-10/9 < -2/3 < 4/6 < 6/5 < 5/4

(hope this helps!)

Step-by-step explanation:

3 0

2 years ago

Tia and Tom are making cupcakes. They need 3/4 a cup of flour and 1/3 cup of butter per batch. If they have 4 1/4 cups of flour

expeople1 [14]

Answer:

5

Step-by-step explanation:

3 0

2 years ago