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The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
(since we minus 1, the highest exponet is 9 so add 1 to make it correct)
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
Answer:
Therefore 80 ceperies will he need to sell this month.
Step-by-step explanation:
Average: Average is the ratio of sum of all numbers to the total number present in the data.
Given that Herbert has sold 99, 37, 86 and 73 copeirs in the last 4 months.
Let he need to sell x copeirs in this month.
According to the problem,
⇒ 99+37+86+73+x= 75×5
⇒295 + x= 375
⇒x = 375 - 295
⇒ x= 80
Therefore 80 ceperies will he need to sell this month.