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2 years ago

The legnth of a rectangle is 1/3 of its width. The width of the rectangle is 9 feet what is the area of the rectangle.

Mathematics

1 answer:

faltersainse [42]2 years ago

3 0

Answer:

The area of the rectangle is 27

Step-by-step explanation:

so we need our formula to find the area of a rectangle. Area = Width × Length

Now we plug our numbers in.

A = 9 × Length

Since we are missing our exact Length amount we need to figure that out first. The statement says the length is 1/3 the size of the Width and the Width is 9.

9 × 1/3 = 9/3

9/3 can be simplified to 3 thus our Length is 3. now we add this into our equation

A = 9 × 3

A = 27

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PLEASE HELP ME!!!!! <br><br> what is the perimeter and area of this figure?

Pavel [41]

Answer:

The perimeter is 99

Step-by-step explanation:

you do 11x9=99

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3 years ago

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sergiy2304 [10]

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2 years ago

Find the constant $a$ such that\[(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28.\]

Colt1911 [192]

The value of constant a is -5

Further explanation:

We will use the comparison of co-efficient method for finding the value of a

So,

Given

$(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\$

As it is given that

(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28

In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x

Comparing coefficient of x^3

$a-6 = -11\\a = -11+6\\a = -5$

So the value of constant a is -5

Keywords: Polynomials, factorization

Learn more about factorization at:

#LearnwithBrainly

4 0

3 years ago

Look at the picture ASAP

goldenfox [79]

Using the Laws of Cosine, we obtain $C^2 = 55^2+108^2-2(108)(55)*cos(59)$ , which c approximately equals 153.44. So Line AB ≈ 153.44 meters.

8 0

2 years ago

Scan domain, range and graph of the following functions:

FinnZ [79.3K]

Sorry can't include the graphs, just subsitute y for f(x) and graph by subsituting values

so domain is the set of numbers you are allowed to use
range is the set of number you get from inputing the numbers from the domain into the function

so normally the domain is all real numbers
you must exclude number from the domain that make mathematical undifined impossible stuff exg dividing by zero so
not sure about the ranges so I will leave that out

a. denomenator is x-2
cannot be zero
x-2=0
add 2
x=2

domain: all real numbers except for 2

b. x+2=deomenator
x+2=0
subtract 2
x=-2
x acannot be -2

domain: all real numbers except for -2

c
x cannot be 0
domain: all real numbers except for 0

d. x cannot be -1
domain: all real numbers except for -1

e: x cannot be a negative number or 0
domain: all real numbers greater than zero

f: x cannnot be -2
domain: al real numbers except -2

g: x cannot be 0
domain: all real number except 0

h: x cannot be zero
domain: all real numbers except 0

i: x cannot be 1
doman: all real number except 1

j: 5x-2=0
add 2
5x=2
divide 5
x=2/5

x cannot be 2/5
domain: all real numbers except for 2/5

5 0

3 years ago