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3 years ago

Please help me. Explain I don’t understand this

Mathematics

2 answers:

s2008m [1.1K]3 years ago

7 0

Answer:

-9

Step-by-step explanation:

-6/2 + -6 =

-6 divided by 2 = -3 =

-3+-6=

-9

BlackZzzverrR [31]3 years ago

3 0

Answer:

-9

Step-by-step explanation:

6/2+-6

/ this is division

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Find the value of x. A. X = 90 B. X = 32 C. X = 30 D. X = 15

Verizon [17]

A or d…………………………… ……

5 0

3 years ago

Read 2 more answers

About 3% of the population has a particular genetic mutation. 600 people are randomly selected.

Annette [7]

Answer:

Standard deviation for the number of people with the genetic mutation = 4.178

Step-by-step explanation:

Explanation:-

Given random sample size 'n' =600

proportion of the Population 'p'=3% or 0.03

Let 'X' be the random variable in binomial distribution

Mean of the binomial distribution

μ = n p

= 600 X 0.03

= 18

Mean of the binomial distribution ' μ ' =18

Standard deviation of the binomial distribution

σ = $\sqrt{npq} = \sqrt{600 X 0.03 X 0.97} = \sqrt{17.46} = 4.178$

Conclusion:-

Standard deviation for the number of people with the genetic mutation = 4.178

8 0

3 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: ordinary differential equation ode integration separable variables initial value problem differential integral calculus

7 0

3 years ago

Order the numbers from least to greatest √99 , 2 , 9.8

spin [16.1K]

Answer:

2, 9.8, $\sqrt{99}$