R=C/2(eliminate "2" from r by dividing both sides by 2)
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
Answer:
$246
Step-by-step explanation:
6 x 9 + 12 x 16= 246
A regular pyramid has a regular polygon base and vertex over the center of the base.
Let x be the expensive scarf. The other scarf costs x-3.
x + (x-3) = 25
2x = 28
x = 14
Answer: 14
