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3 years ago

Find the distance between (-6,4) and (-2,1)

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

4 0

Answer:

$d=2.65$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2-(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the formula to find distance d:

$d=\sqrt{(-2-(-6))^2-(1-4)^2}$

$d=\sqrt{(-2+6))^2-(-3)^2}$

$d=\sqrt{(4)^2-9}$

$d=\sqrt{16-9}$

$d=\sqrt{7}$

$d=2.65$

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The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

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$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
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$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
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