Perpendiculare means the slopes multiply to -1
y=3/5x+10
slope is 3/5
3/5 times what is -1
-5/3 is answer
slope of perpenduclar is-5/3 find y int
y=-5/3+b
point given is (15,-5)
x=15
y=-5
-5=-5/3(15)+b
-5=-25+b
add 25 to both sides
20=b
the yintercept is y=20 or the oint (0,20)
The answer should be c hope this helps
Answer:
Option 2 - Approximately 24–36 pounds
Step-by-step explanation:
Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.
To find : What range of weights would 99.7% of the dogs have?
Solution :
The range of 99.7% will lie between the mean ± 3 standard deviations.
We have given,
Mean weight of Eskimo dogs is
Standard deviation of Eskimo dogs is
The range of weights would 99.7% of the dogs have,
![R=\mu\pm3\sigma](https://tex.z-dn.net/?f=R%3D%5Cmu%5Cpm3%5Csigma)
![R=30\pm3(2)](https://tex.z-dn.net/?f=R%3D30%5Cpm3%282%29)
![R=30\pm6](https://tex.z-dn.net/?f=R%3D30%5Cpm6)
![R=30+6,30-6](https://tex.z-dn.net/?f=R%3D30%2B6%2C30-6)
![R=36,24](https://tex.z-dn.net/?f=R%3D36%2C24)
Therefore, The range is approximately, 24 - 36 pounds.
So, Option 2 is correct.
35.1 is the answer to this question