Area of a circle = pi * r^2
Radius (r) = ½ * diameter
½ * 10 = 5
A= pi * 5^2
25 * pi = 78.54 sq inches
10.99 / 78.54 = about 14 cents per sq in (13.99)
In this item, we are to calculated for the 6th term of the geometric sequence given the initial value and the common ratio. This can be calculated through the equation,
An = (A₀)(r)ⁿ ⁻ ¹
where An is the nth term, A₀ is the first term (in this item is referred to as t₀), r is the common ratio, and n is the number of terms.
Substitute the known values to the equation,
An = (5)(-1/2)⁶ ⁻ ¹
An = -5/32
Hence, the answer to this item is the third choice, -5/32.
Answer:
The last graph with the point (2,4).
Step-by-step explanation:
Make a table of the values, then graph.
Example:
X: -2, -1, 0, 1, 2
Y:
,
,
, 1, 4
<u>Given</u>:
Given that O is the center of the circle.
The radius of the circle is 3 m.
The measure of ∠AOB is 30°
We need to determine the length of the major arc ACB
<u>Measure of major ∠AOB:</u>
The measure of major angle AOB can be determined by subtracting 360° and 30°
Thus, we have;


Thus, the measure of major angle is 330°
<u>Length of the major arc ACB:</u>
The length of the major arc ACB can be determined using the formula,
<u></u>
<u></u>
Substituting r = 3 and
, we get;



Thus, the length of the major arc ACB is 5.5π m