Question

25 points need this answered ASAP: You have two exponential functions. One function has the formula g») = 3(2x). The other function has the formula h(x) =
2^x+1. Which option below gives formula for K(x) = (g- 1)(x)?
Klx) = 2^x
K(X) = 5(2)
K(x) = 5(2^x+1)
K(x) = 2

Answer 1

Answer:

The option A i.e. $k(x)=2^x$ gives the formula for $k(x) = (g-h)(x)$

Step-by-step explanation:

Given the two exponential functions:

• $g(x)=3(2^x)$

• $h(x)=2^{x+1}$

As

$k(x) = (g-h)(x)$

$k(x)= g(x)-h(x)$.......[A]

As

$g(x)=3(2^x)$ and $h(x)=2^{x+1}$

So, putting the values of $g(x)=3(2^x)$ and $h(x)=2^{x+1}$ in equation [A]

$k(x)=g(x)-h(x)$

$\\ =3(2^x)-2^{x+1}$

$=3(2^x)-2(2^{x})$

$\\ =2^x(3-2)$

$=2^x$

Hence, the option A i.e. $k(x)=2^x$ gives the formula for $k(x) = (g-h)(x)$.

Keywords: function, exponential function

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