7 2/5 is a mixed number for 37/5.
1. If the product of these integers is to be 1, then all of them must be either 1 or -1.
2. Since the product is positive (+1), it must be that there are an *even* number of negative ones (-1), if any.
3. If the sum were 0 it would mean that the number of +1's must equal the number of -1's. So that means there would have to be exactly 22/2=11 of each.
4. But if there were 11 of each, that means the number of -1's would be *odd* and there's no way the product could be +1 (as stated in 2 above).
Hence, the sum is never 0, if the product of 22 integers is equal +1.
Answer:
$54.50
Step-by-step explanation:
10% = 10/100
=545 × 10/100
=5450/100
=54.5
Answer:
156
Step-by-step explanation:
f(x)= 4^(2x) -100
Let x =2
f(2)= 4^(2*2) -100
= 4^4 - 100
= 256 -100
= 156
1 1/3 divided by 3/5= 2 2/9. Hope this helps :)
