The proper way to write a single digit whole number in a sentence is:

3. How many gallons of ice-cream are produced each<br>week?

andrezito [222]

Answer:

Each week 26,849,315 Gallons of ice cream is produced each week

Step-by-step explanation:

To find this we see how much is made in a year which is 1.4 billion gallons in the U.S.

To see how much is in a day we divide 1.4 billion by 365. Which is 3835616 Then we multiply it by 7 because there is 7 days in a week and the answer is 26849315

5 0

3 years ago

Please I need help who want to earn 13 points ..

lisov135 [29]

Answer:

Triangle ISK

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Evaluate -3- (-4) - (-2) + 1.

Shtirlitz [24]

Answer:

4

Step-by-step explanation:

-3+4+2+1=4

8 0

3 years ago

The graph below represents which system of inequalities?

mamaluj [8]

The graph below represents y < 2 over 3x − 2 | <span>y > 2x + 2</span> system of inequalities. The answer is letter C. The rest of the choices do not answer teh qustion above

3 0

3 years ago

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Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago