The fraction of a defective item getting by both inspectors is 
= 
Step-by-step explanation:
Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).
Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.
P(A) = 0.1 = 
.
It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) = 
.
Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.
P(A and B happening) = P(A) × P(B) = × = = = 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.
The answer is $ 68 is the answer for the questions
Answer: B.), D.), and E.)
Step-by-step explanation:
That’s the answer on USAtestprep
Answer:
46,499 digits
Step-by-step explanation:
Total pages of book = 11,521
9 pages numbered 1 - 9 that need 1 digit each = 9 × 1
= 9 digits
90 pages numbered 10 - 99 that need 2 digits each = 90 × 2
= 180 digits
900 pages numbered 100 - 999 that need 3 digits each = 900 × 3
= 2,700 digits
9000 pages numbered 1000 - 9999 that need 4 digits each = 9000 × 4
= 36,000 digits
1522 pages numbered 1000 - 11521 that need 5 digits each = 1522 × 5
= 7,610 digits
Total digits needed = 9 digits + 180 digits + 2,700 digits + 36,000 digits + 7,610 digits
= 46,499 digits
65.8 + 13.4 = 79 .2. So the answer is c
