The answer to the question is a direct variation. k=2
1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
y = 2/3(z)(7 - x^2)
2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz
12, 4
take the first number together than the last ones and just find the difference
240
/ \
5 48
/ \
6 8
/ \ / \
3 2 4 2
