The answer
<span>the third rope to counterbalance Sam and Charlie is F
and vectF +vectF1 +vectF2 =vect0
let's consider axis
y'y </span>vectF = -F
vectF 1= F1cos60
vectF 2= F2cos45
-F = -F1cos60-F2co45
so F= F1cos60+F2co45= 350x0.5+400x0.7=457.84 pounds
Answer:
D.
Step-by-step explanation:
When a line is perpendicular to another, their slopes will be opposite reciprocal. For example, 1 would be -1, -3 would be 
, and 
would be -5. The equation is written in slope-intercept form:
m is the slope, so find the equation with the opposite reciprocal of 3, 
:
is the only option with the correct slope, so the answer is D.
That's a 33% increase.
I calculated this using the formula:
Where n = the new value (16 in your question), o = the old value (12 in your question) and the result is outputted as a percent increase. You can check that this is correct by finding 33% of 12, adding the result to 12, and checking that the result equals your "new" number.
Note that 33% is only an approximation as your question requires a number rounded to the nearest whole.
The given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.
What do you mean by absolute maximum and minimum ?
A function has largest possible value at an absolute maximum point, whereas its lowest possible value can be found at an absolute minimum point.
It is given that function is f(x) = |x + 3|.
We know that to check if function is absolute minimum or absolute maximum by putting the value of modulus either equal to zero or equal to or less than zero and simplify.
So , if we put |x + 3| = 0 , then :
± x + 3 = 0
±x = -3
So , we can have two values of x which are either -3 or 3.
The value 3 will be absolute maximum and -3 will be absolute minimum.
Therefore , the given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.
Learn more about absolute maximum and minimum here :
brainly.com/question/17438358
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<h3>
Answer:</h3>
System
Solution
- p = m = 5 — 5 lb peanuts and 5 lb mixture
<h3>
Step-by-step explanation:</h3>
(a) Generally, the equations of interest are one that models the total amount of mixture, and one that models the amount of one of the constituents (or the ratio of constituents). Here, there are two constituents and we are given the desired ratio, so three different equations are possible describing the constituents of the mix.
For the total amount of mix:
... p + m = 10
For the quantity of peanuts in the mix:
... p + 0.2m = 0.6·10
For the quantity of almonds in the mix:
... 0.8m = 0.4·10
For the ratio of peanuts to almonds:
... (p +0.2m)/(0.8m) = 0.60/0.40
Any two (2) of these four (4) equations will serve as a system of equations that can be used to solve for the desired quantities. I like the third one because it is a "one-step" equation.
So, your system of equations could be ...
___
(b) Dividing the second equation by 0.8 gives
... m = 5
Using the first equation to find p, we have ...
... p + 5 = 10
... p = 5
5 lb of peanuts and 5 lb of mixture are required.
