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tamaranim1 [39]
3 years ago
13

Write an equation for a line that is parallel to 2x+5y=15 and passes through the point (-10, 3)​

Mathematics
2 answers:
aleksley [76]3 years ago
5 0

Answer:

the equation of a parallel line is : y=-2/5 x -1

Step-by-step explanation:

2x+5y=15

put the equation in the form of y=mx+b

2x+5y=15

5y=15-2x

y=15/5-2/5 x

y=-2/5 x+3

parallel lines has the same slope : m=-2/5

passes through point (-10,3) find b

y=-2/5 x +b

3=-2/5(-10)+b

3=20/5 +b

3=4+b

b=3-4

b=-1

the equation of a parallel line is : y=-2/5 x -1

Lyrx [107]3 years ago
3 0

Answer:

The equation of the line is,

y =  -  \frac{2}{5} x - 1

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

2x + 5y = 15

5y = 15 - 2x

y = 3 -  \frac{2}{5} x

y =   - \frac{2}{3} x + 5

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

y =   - \frac{ 2}{5}x + b

let \: x =  - 10,y = 3

3 =  -  \frac{2}{5} ( - 10) + b

3 = 4 + b

3 - 4 = b

b =  - 1

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