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pogonyaev
3 years ago
8

Possible names for a rectangle​

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Step-by-step explanation:

A rectangle can be called a: 1) quadrilateral because it is 4 sided. 2) polygon because it is a closed figure with at least 3 sides. 3) parallelogram because it has 2 pairs of sides that are parallel.

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Please explain how you got he answer no links please :)
charle [14.2K]

Answer:

4 is the gradient

Step-by-step explanation:

choose any two coordinate then apply the gradient equation

10-2= 8

3-1= 2

8/2= 4

4 is the gradient

5 0
3 years ago
Three times a number less than the sum of twice the number and 1
BabaBlast [244]
That would be 3n<2n+1
4 0
3 years ago
I’m going to need a serious answer through this one or I’m screwed.
Elina [12.6K]

Answer:

A = 60 ft²

Step-by-step explanation:

the area (A) of the shaded sector is calculated as

A = area of circle × fraction of circle

   = 90 × \frac{240}{360}

   = 90 × \frac{2}{3}

    = 30 × 2

    = 60 ft²

5 0
2 years ago
Read 2 more answers
Please help with by finding the surface area of numbers 122 to 124 which are the top one ands please read 125 a and 126 to find
Annette [7]
Surface area of cylinder is 2 (pi)rh+2(pi)r^2
this is the area of the side [(2 (pi)rh] and the two circles together [2 (pi)r^2]

122. r=24
h=15
2 (3.14)24×15+2 (3.14)24^2
6.28×24×15+6.28×24^2
2260.8+3617.28
5878.08mm

123. r=5
h=8
2 (3.14)5×8+2 (3.14)5^2
6.28×5×8+6.28×5^2
251.2+157
408.2cm

124. the surface area of a cylinder that has a hole is going to be
surface area of big cylinder-2small area circles (the holes) + the area of the holes sides

hopefully that isn't too confusing

big radius: 8
height: 14

little radius: 2.5
height: 14

2 (3.14)8×14+2 (3.14)8^2
6.28×8×14+6.28×8^2
703.36+401.92

1105.28in (area of big cylinder)

2 (3.14)2.5^2 (two small holes)
6.28×2.5^2
39.25in (area of holes)

2 (3.14)×2.5×14 (area of side)
6.28×2.5×14
219.8in

1105.28-39.25+219.8
1066.03+219.8

1285.83in total surface area

125. h=20
r=6 since diameter is a foot or 12 in, half of that is 6
2 (3.14)6×20+2 (3.14)6^2
6.28×6×20+6.28×6^2
753.6+226.08
979.68in

126. first radius= 10
first height = 6

second radius= 6
second height= 10

2 (3.14)10×6+2 (3.14)10^2
6.28×10×6+6.28×10^2
376.8+628
1004.8in (surface area of first cylinder)

2 (3.14)6×10+2 (3.14)6^2
6.28×6×10+6.28×6^2
376.8+226.08
602.88in (surface area of second cylinder)

1004.8-602.88= 401.92

the surface area of the cylinder with radius 10 and height 6 is GREATER that the surface area of the cylinder with radius 6 and height 10..
by 401.92in
8 0
3 years ago
Help me please 7−s/2&gt;3
Alja [10]

Answer:

s < 8

Step-by-step explanation:

7−s/2>3

Subtract 7 from each side

7-7−s/2>3-7

-s/2 > -4

Multiply each side by -2.  Remember to flip the inequality since we are multiplying by a negative.

-s/2 * -2 < -4*-2

s < 8

3 0
4 years ago
Read 2 more answers
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