A. The scores in order are: 10, 12, 13, 14, 14, 16, 18, 23, 24, 26. The range is 26 - 10 = 16. The mean is the sum divided by 10, which is 17. The median is between 14 & 16, which is 15. The mode is 14, since it is repeated twice.
B. The variance is calculated by subtracting each score from the mean, squaring, and adding all such squares. Then divide by the number of terms (10) to get 27.6 Take the square root to get the standard deviation, which is 5.25.
C. This is for a population, since these are all 10 games that Jason played. (If it were a sample, we would divide by 9 only)
D. The mean of 17 is higher than the median of 15 and the mode of 14. This implies a left-skewed distribution. However, the SD of 5.25 is quite high relative to the mean of 17, so the distribution is not that clearly defined yet (more data points would make it clearer).
Essentially, 50% of $10.56 is $5.28.
This means that all we have to do is add $10.56 to $5.28, making <u>$15.84</u>
Side note: Another way that you can do this is by simply doing 1.5(10.56).
<span>3[(15 - 3) squared divided by 4]
=</span><span>3[(15 - 3)^2 / 4]
=3</span>[(12)^2 / 4]
=3[144 / 4]
=3[36]
=108
