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d1i1m1o1n [39]
3 years ago
15

What is the value of x? Enter your answer in the box.

Mathematics
2 answers:
Stels [109]3 years ago
7 0
Use (n - 2) × 180 to find the sum of the measures of the interior angles of the polygon, where n = number of sides of the polygon.
The polygon has 7 sides, so plug 7 in for n.

(7 - 2) × 180 = 900
The sum of the interior angles of this 7-gon is 900°.

Now that we know this, make an equation where all the interior angles add up to 900, then solve for x.

∠A + ∠B + ∠C + ∠D + ∠E + ∠F + ∠G = 900° ⇒
146 + 122 + 142 + 140 + 110 + 142 + x = 900
802 + x = 900
Subtract 802 from both sides.

x = 98°
pshichka [43]3 years ago
4 0
Hello!

The sum of all angle measures in a heptagon in 900°. We will subtract all of these angles from 900 to find our answer.

900-146-122-142-140-110-142=98

x=98°

I hope this helps!
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the sum of 2 positive integers is 10. the difference of their reciprocals is 3/8. find both positive integers
Elena-2011 [213]

Answer:

The 2 integers would be: 2 and 8

Step-by-step explanation:

2 + 8 = 10

Reciprocal of 2: 1/2

Reciprocal of 8: 1/8

1 / 2 - 1 / 8 = 4/8 - 1/8 = <u>3/8</u>

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2 years ago
Solve the system of equations:
PolarNik [594]

Answer:

D.(-1,-5) and (5,7)

Step-by-step explanation:

I used a graphing tool to graph the two equations together. When graphed, the equations intercept (5,7) and (-1,-5). Therefore, they are the solutions to the system.

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3 years ago
How to find the average squared distance between the points of the unit disk and the point (1,1)
ddd [48]
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)
=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
=r^2-2r(\cos\theta-\sin\theta)+2

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
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3 years ago
Simplify: 40÷4+2×6÷4-3
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Simplify the experssion and you get 10.
Hope this helps!
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3 years ago
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