1) The triangles are similar, so correponding sides have the same ratio.
.. 3x/20 = (4x +2)/28
.. 3x/5 = (4x +2)/7 . . . . . . . multiply by 4
.. 7*3x = 5(4x +2) . . . . . . . multiply by 35 = 5*7
.. 21x = 20x +10 . . . . . . . . eliminate parentheses
.. x = 10 . . . . . . . . . . . . . . . subtract 20x
2) The triangles are similar, so corresponding measures have the same ratio.
.. x/42 = 10/15
.. x = 42*(10/15) = 28
3) The third angle of triangle ABC is 180° -20° -80° = 80°. Then two of the angles of ABC match those of JKL. The 3rd answer selection is appropriate.
Answer: 35 additional teachers are needed
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Explanation:
We have 2470 students and the ratio of students to teachers is 26:1. This means that for every teacher, there are 26 students. Put another way, we can set up this ratio
2470/x = 26/1
where x is the number of teachers. Cross multiply and solve for x
2470/x = 26/1
2470*1 = 26*x
2470 = 26x
26x = 2470
26x/26 = 2470/26
x = 95
So we have 95 teachers currently
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Let y be the new number of teachers needed to bring the ratio down to 19:1
Using a similar idea as done above, we would have this ratio
2470/y = 19/1
Let's solve for y
2470/y = 19/1
2470*1 = 19*y
2470 = 19y
19y = 2470
19y/19 = 2470/19
y = 130
So we'll need 130 teachers to have the ratio be 19:1
The difference of the values is y - x = 130 - 95 = 35, which is the final answer. This is the additional amount of teachers needed.
The answer is 3p+6 gggghhnbhjjn
For the first one the nth term is 9n - 8 so the 10th term is 9x10 - 8 = 90-8 = 82
For the second one the nth term is ⅓n + ⅓ so the 11th term is ⅓x11 +⅓ = 3.9999 = 4
Since the slope is rise/run, 1/6 goes up one, right 6. Perpendicular is opposite that. so a slope of -6 goes down 6 and right 1. (as a fraction it's -6/1)
