Answer:
x(3x+14)
Step-by-step explanation:
what do those terms share? they share the letter "x"
therefore we multiply x by 3x^2/x + 14x/x
3x^2/x = 3x and 14x/x = 14
The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
<h3>
Answer: 28/57</h3>
Explanation:
The odds in favor of 28 to 29 means there are 28 ways the event E could occur and 29 ways it doesn't occur.
So there are 28 instances out of 28+29 = 57 ways total.
It leads to the fraction 28/57 which cannot be reduced further.
Answer:
14:42
Step-by-step explanation:
As we got 2 to get to 14, that means that we need to times by 7. Then we times the 6 by 7 to get the answer of 42.
Distance = rate*time
convert minutes to hour first because the question talking about 15 mile per hour
40 mins = 40/60 2/3 hrs
30 mins = 30/60 = 1/2hrs
Assume that s be the speed when Fritz driving, so
s + 15 will be the speed of the train.
We know the time we know the speed, Next
distance that Fritz drive =

distance the train travel =

The question: Assume that the train travels the same distance as the car
==>

==>

==>

==>

==>

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Now we know that Fritz drive at 45 mph,
distance =