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notka56 [123]
3 years ago
8

130 135 1

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0
Are these all different questions?
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Please help me solve this :)
Svetradugi [14.3K]

In given picture we see that there are total 8 boxes out of which only 5 are shaded.

So the number that represents shaded part will be 5/8.

But we have to find which choice doesn't indicate shaded part.

So we will pick those choices which are not equivalent to 5/8.

5/8=0.625

if you convert that into percent then we get (5/8)100%=62 1/2 %

that means 5/8, 0.625, 62 1/2 % all represents same thing and represent shaded part.

So the remaining choice a) 0.582 is the final answer .

7 0
3 years ago
A line segment AB has the coordinates A (2,3) AND B
Ugo [173]
4i think I remember taking a test but don’t blame me if it’s wrong
5 0
3 years ago
heather works as a waitress at her family restaurant. she works 2 hours every morning during the breakfast shift and returns to
Marrrta [24]

Answer:

3.6 hours per evening shift

Step-by-step explanation:


5 0
3 years ago
How do you get angle x using trigonometry in a right angled triangle?
Scorpion4ik [409]

Answer:

Example

Step 1 The two sides we know are Adjacent (6,750) and Hypotenuse (8,100).

Step 2 SOHCAHTOA tells us we must use Cosine.

Step 3 Calculate Adjacent / Hypotenuse = 6,750/8,100 = 0.8333.

Step 4 Find the angle from your calculator using cos-1 of 0.8333:

3 0
3 years ago
Need Help with the composition of two rational functions. screenshot is below
igomit [66]

We just have to write one function inside the other:

(f\circ g)(x) = f(g(x))\\\\(f\circ g)(x) = f\left(\dfrac{13}{x+3}\right)\\\\(f\circ g)(x) = \dfrac{2}{\left(\dfrac{13}{x+3}\right)+3}\\\\(f\circ g)(x) = \dfrac{2}{~~\dfrac{13+3(x+3)}{x+3}~~}\\\\(f\circ g)(x) = \dfrac{2(x+3)}{13+3(x+3)}\\\\\boxed{(f\circ g)(x) = \dfrac{2x+6}{3x+22}}

Since we have a fraction with x in the denominator, we have to remove from the domain the value of  that makes null the denominator. Thus,

3x+22\neq0\Longrightarrow 3x\neq22\Longrightarrow x\neq \dfrac{22}{3}

Furthermore, we also have to remove the value of x that annuls the denominator of g(x), because that's the first function that we use. So:

x+3\neq0\Longrightarrow x\neq-3

Hence, the domain is:

D((f\circ g)(x)) = \left]-\infty,-3\right[\cup \left]-3,\dfrac{22}{3}\right[\cup\left]\dfrac{22}{3},\infty\right[

3 0
4 years ago
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