Answer:
P_max = 9.032 KN
Step-by-step explanation:
Given:
- Bar width and each side of bracket w = 70 mm
- Bar thickness and each side of bracket t = 20 mm
- Pin diameter d = 10 mm
- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa
- Average allowable shear stress of pin S = 115 MPa
Find:
The maximum force P that the structure can support.
Solution:
- Bearing Stress in bar:
T = P / A
P = T*A
P = (120) * (0.07*0.02)
P = 168 KN
- Shear stress in pin:
S = P / A
P = S*A
P = (115)*pi*(0.01)^2 / 4
P = 9.032 KN
- Bearing Stress in each bracket:
T = P / 2*A
P = T*A*2
P = 2*(120) * (0.07*0.02)
P = 336 KN
- The maximum force P that this structure can support:
P_max = min (168 , 9.032 , 336)
P_max = 9.032 KN
Answer:
5
Step-by-step explanation:
Special triangle. 1:1:
Answer:costC(p)= 1400+20p
R(p)= 4p^2+200p
Profit= 4p^2+ 180p-1400
Step-by-step explanation:
q=4p+200
Student council charge $400 per week.
Revenue= price × quantity.
Relationship between revenue and profit= Revenue-total cost.
Total cost= cost of facilities +(cost of one shirt)× number of T-shirts sold per week.
C(p)= 400 + 5(q)
Put q=4p+200
C(p)= 400 + 5 (4p +200)
C(p)= 400+ 20p + 1000
C(p)= 1400+ 20p
Relationship between revenue and price=Revenue= price × quantity
R(p)= p×q
Put q=4p +200
R(p)= p ×(4p +200)
R(p)= 4p^2+ 200p
Profit= Revenue - total cos
Profit=R(p) -C(p)
Profit= (4p^2 + 200p) - ( 20p +1400)
Profit= 4p^2 + 180p -1400
See what’s on -3 and there’s ya answer jejjrheggehehudjeytwgegbsnwj
Circumference is pi*diameter, so 94.2/ pi = 30, so the answer is C. 30 in
