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dybincka [34]
2 years ago
8

Help pealse.............

Mathematics
2 answers:
Pavlova-9 [17]2 years ago
7 0

Answer:

15 degrees Celsius is 59 degrees Fahrenheit. I'm not sure what to do with the expression, though.

Step-by-step explanation:

I don't really have one.

Zielflug [23.3K]2 years ago
5 0

Answer:

59

Step-by-step explanation:

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What is the area of a rectangles with the side lengths 5 inches and 1/3 inches? ​
sveticcg [70]

Answer:

area of a rectangle is length multiplied by breath, which is the multiplication of 5 an 1/3

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3 years ago
WILL MARK BRAINLIEST!!!!!!!!
SVETLANKA909090 [29]

Data:

15 16 14 15 19 17

n=6 points

sum is 96

mean is 96/6 = 16

Now we look at the absolute deviations, each of which is the absolute value of a score minus the mean, basically the distance of the score to the mean .

Scores   15 16 14 15 19 17

AbsDev    1  0  2  1    3  1

The sum of the absolute deviations is 8 and there are six of them so the

Mean Absolute Deviation = 8/6 = 4/3

Answer: 2.    8/6

7 0
3 years ago
Reason A pack of 140 stickers contains sheets of 28 stickers. Each
xxTIMURxx [149]

Answer:

you could divide

Step-by-step explanation:

4 0
3 years ago
Use pemdas (18 - 14) x (4 x 2) write 3 steps
Deffense [45]

Answer:

32

Step-by-step explanation:

Parentheses:

(18 - 14) = 4

(4 x 2) = 8

4 x 8

Multiplication:

4 x 8 = 32

<em>good luck hope this helps :)</em>

7 0
3 years ago
Read 2 more answers
The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi
yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let p_1 = <u><em>percentage of employed workers who have registered to vote.</em></u>

p_2 = <u><em>percentage of unemployed workers who have registered to vote.</em></u>

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, H_A : p_1>p_2     {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here <u>Two-sample z test for proportions;</u>

                          T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of employed workers who have registered to vote = \frac{287}{513} = 0.56

\hat p_2 = sample proportion of unemployed workers who have registered to vote = \frac{280}{604} = 0.46

n_1 = sample of employed persons = 513

n_2 = sample of unemployed persons = 604

So, <u><em>the test statistics</em></u>  =  \frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }

                                       =  3.349

The value of z test statistics is 3.349.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0
3 years ago
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