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3 years ago

Which one is greater? 4/9 (fraction) or 0.4 (decimal)

Mathematics

2 answers:

Fudgin [204]3 years ago

6 0

Answer:

4/9 is greater.

Step-by-step explanation:

4/9= .4444444... repeating

.4444444∞>.4

I hope this was helpful, have a lovely day!!!

blsea [12.9K]3 years ago

3 0

Answer:

The answer is simple they are equal

Step-by-step explanation:

This is because 4/9 is 0.44444444 repeated

0.4 by itself is obviously 0.4

HOPE THIS HELPS!!!

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A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when

Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

given data:

mean, $\bar X = 58.3$

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

$ME = Zc * σ \sqrt{n}$

$ME = 1.96 * 3 \sqrt{25}$

ME = 1.18

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})$

CI = (57.12 , 59.48)

Given data:

mean, $\bar X = 58.3$

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

$ME = zc * σ \sqrt{n}$

$ME = 1.96 * 3\sqrt{100}$

ME = 0.59

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})$

CI = (57.71 , 58.89)

sample mean, $\bar X = 58.3$

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

$ME = Zc * σ \sqrt{n}$

$ME = 2.58 * 3\sqrt{100}$

ME = 0.77

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}$

CI = (57.53 , 59.07)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

$n \geq (zc *σ/E)^2$

$n = (2.58 * 3/0.5)^2$

n = 239.63

7 0

4 years ago

Which questions are statistical questions?

Yanka [14]

Answer:

Which questions are statistical questions?

what is the number of students what is the height of each in my class?

how many servings of fruit did eat each day this month?

what is my height?

what is the highest temprature

of each month this year?

how many students from each school in this city love football?

Step-by-step explanation:

Need to include numerical values

8 0

4 years ago

PLss answer I will give brainliest

marshall27 [118]

Answer:

I pretty sure it's 3/14

Step-by-step explanation:

There are 6 small fish and 8 large fish- find the total. 6+8=14 (14 will be the denominator)

Half of the small fish are red so 6/2=3 (3 is the numerator)

The probability of you picking one small red fish is 3/14

7 0

3 years ago

Determine the fraction of total interest owed using the rule of 78. After the six month of a 12 month loan, the numerator is: {(

Dima020 [189]

Answer:

The fraction of total interest owed is $\frac{57}{78}$

The value of it to the nearest tenth is 73.1%

Step-by-step explanation:

Let us solve it using the rule of 78

∵ The loan = 12 month

∵ The numerator is after 6 month

- Substitute n by 1 in each bracket

∴ The numerator = {(1 + 11) + (1 + 10) + (1 + 9) + (1 + 8) + (1 + 7) + (1 + 6)}

∴ The numerator = {12 + 11 + 10 + 9 + 8 + 7}

∴ The numerator = {57}

∴ The numerator of the fraction is 57

∵ The denominator = {(n) + (n + 1) + (n + 2) + .......... + (n + 11)}

- substitute n by 1 in each bracket

∴ The denominator = {1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12}

∴ The denominator = {78}

∴ The denominator of the fraction is 78

The fraction of total interest owed is $\frac{57}{78}$

Now find the value of the fraction

∵ The fraction = $\frac{57}{78}$

∴ Its value = 0.7307692308 × 100%

∴ Its value = 73.07692308%

- Round it to the nearest tenth

∴ Its value = 73.1%

The value of it to the nearest tenth is 73.1%

5 0

3 years ago

Sandi randomly selects a single bill from an envelope containing 8 ones, 5 fives, 4 tens, and 3 twenties. What is the expected v

AnnZ [28]

Answer:

The expected value of the money she selects is 6.65.

Step-by-step explanation:

Expected value:

Sum of each outcome multiplied by its probability.

We have:

8 + 5 + 4 + 3 = 20 total bills.

8 are ones, so P(X = 1) = 8/20 = 0.4.

5 are fives, so P(X = 5) = 5/20 = 0.25.

4 are tens, so P(X = 10) = 4/20 = 0.2

3 are twenties, so P(X = 20) = 3/20 = 0.15.

What is the expected value of the money she selects?

$E(X) = 0.4*1 + 0.25*5 + 0.2*10 + 0.15*20 = 6.65$

The expected value of the money she selects is 6.65.

5 0

3 years ago

Which one is greater? 4/9 (fraction) or 0.4 (decimal)​

Which one is greater? 4/9 (fraction) or 0.4 (decimal)