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DaniilM [7]
4 years ago
14

write the equation of a line in slope intercept form that is parallel to the line x+5y=10 and goes through the point (-5,6)

Mathematics
1 answer:
lilavasa [31]4 years ago
4 0

Answer:

The equation would be y = -1/5x + 5

Step-by-step explanation:

To find the equation of this new line, we first need to identify the slope of the first line. We do this by putting it into slope intercept form.

x + 5y = 10

5y = -x + 10

y = -1/5x + 2

In slope-intercept form, the slope is always the coefficient of x. This makes the slope of the first equation -1/5. Since parallel lines have the same slope, our new slope will also be -1/5.

Given that and the point, we can solve for the equation using point-slope form.

y - y1 = m(x - x1)

y - 6 = -1/5(x + 5)

y - 6 = -1/5x - 1

y = -1/5x + 5


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All tubes of watercolor paint at an art supply store have the the same price. An artist has a coupon for $0.50 off each tube of
BlackZzzverrR [31]

Let us assume the regular price of each tube of paint = r.

0.50 off each tube.

New price of each tube = r - 0.50.

She buy 6 tubes.

Total price of 6 tubes = 6×(r-0.50).

We are given total price = $84.30 .

Therefore, we can setup an equation

6×(r-0.50) = 84.30.

Distributing 6 over (r-0.50), we get

6r - 3.0 = 84.30

Adding 3.0 on both sides, we get

6r - 3.0+3.0 = 84.30+3.0

6r = 87.30

Dividing both sides by 6, we get

6r/6 = 87.30/6

r = 14.55

<h3>Therefore, required equation is 6(r-0.50) = 84.30 and the regular price of each tube of paint is $14.55.</h3>
5 0
3 years ago
Does anyone know how to solve this?
Bezzdna [24]

Use this version of the Law of Cosines to find side b:

b^2 = a^2 + c^2 − 2ac cos(B)

We want side b.

b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)

After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.

Try it....

6 0
3 years ago
9 divided by 5/9 equals what as a fraction
Stels [109]

Answer:

the answer is 1/5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help me i need to complete this by tomorrow
lisov135 [29]

Answer:

Step-by-step explanation: Need to work out your scale factor which is 1.5.

8 * 1.5 = 12

CE = 12

12 * 9 = 108/2 = 59 that is the area of triangle ACE

8 * 6 = 48/2 = 24 that is the area of triangle BCD

ACE - BCD = ABDE

59 - 24 = 35cm^2

8 0
2 years ago
Find the cost of leveling a badminton court 132m long and 58 m broad at the rate of Rs. 80 per sq. m.
serg [7]

Answer:

Rs. 612,480

Step-by-step explanation:

Hi there,

Here the question asks us to find the cost of leveling a badminton court at the rate of Rs.80 per sq..

So by the word leveling we know that we have to find the area of the court in order to proceed further.

<em>(I am assuming the court to be rectangular in shape).</em>

Area of a rectangle = Length * Breadth

*Length = 132 meters

*Breadth = 58 meters

==> 132*58= 7656 m^2

So now that we got the area of the badminton court lets find the cost of leveling it ==>

Cost of leveling per meter^2 = Rs. 80

Area = 7656 m^2

==> 7656 * 80 = 612,480

So the cost would be <u>Rs. 612,480</u>

<u></u>

<u></u>

<u><em>If you found this answer helpful please mark me as brainliest.</em></u>

8 0
2 years ago
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