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3 years ago

write the equation of a line in slope intercept form that is parallel to the line x+5y=10 and goes through the point (-5,6)

Mathematics

1 answer:

lilavasa [31]3 years ago

4 0

Answer:

The equation would be y = -1/5x + 5

Step-by-step explanation:

To find the equation of this new line, we first need to identify the slope of the first line. We do this by putting it into slope intercept form.

x + 5y = 10

5y = -x + 10

y = -1/5x + 2

In slope-intercept form, the slope is always the coefficient of x. This makes the slope of the first equation -1/5. Since parallel lines have the same slope, our new slope will also be -1/5.

Given that and the point, we can solve for the equation using point-slope form.

y - y1 = m(x - x1)

y - 6 = -1/5(x + 5)

y - 6 = -1/5x - 1

y = -1/5x + 5

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Step-by-step explanation:

$25x^2-30x+25=0$

$x_{1,\:2}=\frac{-\left(-30\right)\pm \sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}}{2\cdot \:25}$

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konstantin123 [22]

$\boxed{a=\frac{r+d}{c}}$

<h2>Explanation:</h2>

Here we have the following expression:

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<h2>Learn more:</h2>

Solving equations: brainly.com/question/10643312

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