Coordinates of the given triangle ΔPQR P(1,-1), Q(3,-2), R(3,-4).
a) Let us discuss the rule for rotation of 90° clockwise about the origin.
If given coordinate is (h,k) is rotated 90° clockwise about the origin the position of rotated coordinate will be (k, -h).
x and y coordinates would switch their values and after switching x any values, the y value of the coordinates would reverse in sign.
So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become
P(1,-1) --> P'(-1,-1)
Q(3,-2) --> Q'( -2,-3)
R(3,-4) --> R'(-4,-3)
b) If given coordinate is (h,k), the coordinates after reflection across the x-axis would besome (h,-k). (Just change in the sign of y-coordinate).
So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become
P(1,-1) --> P"(1,1)
Q(3,-2) --> Q"( 3,2)
R(3,-4) --> R"(3,4)
Answer: x≥ 8.00 and x < 9.50 is the correct option.
Step-by-step explanation:
Since, given expression 8.00 ≤ x < 9.50
Where x is the value for which college students are paid hourly as teacher assistants.
so, x is greater than or equal to 8.00
Therefore,
And, x is less than 9.50
Therefore, x < 9.50
On combining both expression we get, and
.
Thus, Third Option is correct.
Answer:
Total surface area of the prism = 920 cm²
Step-by-step explanation:
Given prism has 2 similar triangular surfaces and 3 rectangular surfaces of different dimensions.
Area of one triangular side =
Area of 2 similar sides = Base × Height
= 8 × 15
= 120 cm²
Area of rectangular side with dimensions 17cm × 20cm
Area of the side = 17 × 20 = 340 cm²
Area of the second rectangular side with dimensions 8cm × 20cm
Area of the side = 8 × 20 = 160 cm²
Area of third rectangular side with dimensions 20cm × 15cm
Area of the side = 20 × 15 = 300 cm²
Total surface area of the given triangular prism = 120 + 340 + 160 + 300
= 920 cm²