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jekas [21]
4 years ago
9

I can't do this one

Mathematics
1 answer:
Nikitich [7]4 years ago
4 0
The answer is F.) 0= x^2 - 15x + 54
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What is the volume of the solid generated when the region in the first quadrant bounded by the graph of y=x^3, the x-axis, and t
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Answer:

The first thing we need to do is to find the area bounded by:

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This is the integral of the given function between x = 0 and x = 2, written as:

\int\limits^2_0 {x^3} \, dx = \frac{2^4}{4}  - \frac{0^4}{4} = 2^2 = 4

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Now, if we do a full rotation around the x-axis, the volume generated will be equal to the area that we obtained times 2*pi units.

The volume is:

V = (4 square units)*(2*pi units) = 8*pi cubic units.

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3 years ago
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Step-by-step explanation:

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7 0
2 years ago
Can u help me find the answer please
Flura [38]
There's an indefinite number of answers.  
Only can be solved by a graph.

Are you trying to graph it?
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