Question

Help quickly please!

Answer 1

Answer:

Step-by-step explanation:

Given: $GF=\frac{1}{2}GC$,

$GE=\frac{1}{2}GD$ and $EF=\frac{1}{2}DC$

To prove: ΔGFE is similar to ΔGCD.

Proof: Since, $\frac{GF}{GC}=\frac{1}{2}$, $\frac{GE}{GD}=\frac{1}{2}$ and $\frac{EF}{DC}=\frac{1}{2}$, therefore

$\frac{GF}{GC}=\frac{GE}{GD}=\frac{EF}{DC}$

Hence, by transitive property of equality, ΔGFE is similar to ΔGCD.