For this problem, we are going to have to use our order of operations, which is: Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction (often abbreviated PEMDAS).
First, let's see if there are any parentheses. There is one set of parentheses which we will have to remove. To do this, we will simply multiply the -4 by the 6, given us a value of -24 to take the place of the -4(6). Now our problem is:

Next, we will check for exponents. There are exponents, so we will need to take care of those.
is equal to 144, and
is equal to 121. We can now substitute these values into the original expression to get:

Now, we will check for any multiplication or division. Besides the entire expression (which is a fraction), there is none, so we will move on to the next step: Addition and Subtraction. You can see there is addition and subtraction in the numerator.
is equal to 120, and
is equal to 121. Our problem is now:

Our answer is 1.
Answer:
5. 78.54
6. C
7. 254.47
8. 50.25
Step-by-step explanation: :) Remember, the radius is just half of the diameter. So if the Diameter is 18, the radius is 9.
3x + 2y = 39
-3x -3x
2y = 39-3x
— ———
2 2
y= 19.5 - 3x/2
plug (19.5 - 3x/2) for y
1.5x - 2(19.5 - 3x/2)= 39
x= 17.33333333334
The solution is (-4,4)
Explanation: just plug both equations into desmos; the solution is found by looking at where the graphs of 2x+y=-4 and y=-1/2x+2 intersect.
Answer:
ABC shaded area = 36
- 72 cm²
ABC shaded area perimeter =
cm
ABCD area =
cm²
ABCD perimeter =
cm
Step-by-step explanation:
<u>Shape ABC</u>
Assuming you want the area and perimeter of the shaded part of the shape only...
<u>Area</u>
Area of a sector =
(where r is the radius and
<em> </em>
⇒ area of a sector = 
Area of triangle = 1/2 x base x height
⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²
Therefore, area of shaded area = area of sector - area of triangle
⇒ area = 36
- 72 cm²
<u>Perimeter</u>
Arc length =
(where r is the radius and
<em> </em>
⇒ arc length = 
Hypotenuse of triangle =
(where a and b are the legs of the right triangle)
⇒ hypotenuse =
cm
Therefore, perimeter = arc length + hypotenuse
⇒ perimeter =
cm
<u>Shape ABCD</u>
<u>Area</u>
Area of a semicircle =
(where r is the radius)
⇒ area of large semicircle ABC = 
⇒ area of small semicircle AD = 
⇒ area of shape ABCD = 
<u>Perimeter</u>
1/2 circumference = 
⇒ perimeter = 