If you notice the picture below

the composite figure is just a trapezoid sitting on top of a rectangle
and then, the rectangle has a triangular hole in it

so.. get the area of the trapezoid $\bf \textit{area of a trapezoid}=A=\cfrac{h}{2}(a+b)\qquad 
\begin{cases}
h=height\\
a,b=\textit{parallel sides or bases}
\end{cases}$

then get the area of the rectangle, which is just a 12x14
and then get the area of the triangle, which surely you know is 1/2 bh

then, subtract the triangle's area from the rectangle's area

and whatever is left, namely the difference, add that to the area of the trapezoid, and that's the composite's area

namely the area of the trapezoid plus the rectangle's, minus the triangle's

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3 years ago