Question

You are testing two food scales for accuracy by weighing two different types of foods.

Answer 1

I got sample two......I hope this helps but im 50% sure I might be wrong sorry, please don't hate me if I get it wrong

Answer 2

Answer:

Sample 2 has least percent error.

Step-by-step explanation:

The formula for percent error is

$E=\frac{\text{Stated amount-Actual amount}}{\text{Actual amount}}\times 100$

Percent error in sample 1:

$E_1=\frac{14-13.7}{13.7}\times 100\approx 2.19$

The percent error in sample 1 is 2.19.

Percent error in sample 2:

$E_2=\frac{24-24.4}{24.4}\times 100\approx -1.64$

The percent error in sample 2 is 1.64.

Percent error in sample 3:

$E_3=\frac{25-25.8}{25.8}\times 100\approx -3.1$

The percent error in sample 3 is 3.1.

Percent error in sample 4:

$E_4=\frac{39-40.2}{40.2}\times 100\approx -2.99$

The percent error in sample 4 is 2.99.

Therefore sample 2 has least percent error.