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o-na [289]
3 years ago
6

In a rhombus with a side of 34, the longer diagonal is 26. Find, to the nearest degree, the larger angle of the rhombus

Mathematics
1 answer:
Kitty [74]3 years ago
4 0
The numbers do not seem to work out, lol.

A rhombus has diagonals intersect at right-angles.  All four sides of a rhombus are equal.  So we end up with four right-angled triangle with a hypotenuse of 34, and one leg equal to the half (long) diagonal of 13.
This makes the other leg about 31 long, or a diagonal of 62, longer than the "long diagonal" of 26.

I suspect the question should read the longer semi-diagonal is 26.
Based on that, the other leg is sqrt(34^2-26^2)=21.91.
The greater half-angle therefore has a tangent of 26/21.91=1.1867, and the corresponding half-angle is 49.88 degrees.
The larger angle of the rhombus is therefore 2*49.88=99.76 degrees.
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If the angles of a convex octagon are 2x+6,x+13,2x-1,2x+12,2x-17,3x-4,3x-10,4x. then the smallest angle is 21°.

Given The exterior angles of convex octagon are 2x+6,x+13,2x-1,2x+12,2x-17,3x-4,3x-10,4x.

and we have to find the value of smallest angle.

The sum of the  angles of a convex octagon is 360°

so to calculate the smallest angle we need to find out the value of x first and which is calculated by summing up all the exterior angles and put them equal to 360.

(2x+6)+(x+13)+(2x-1)+(2x+12)+(2x-17)+(3x-4)+(3x-10)+4x=360

2x+6+x+13+2x-1+2x+12+2x-17+3x-4+3x-10+4x=360

2x+x+2x+2x+2x+3x+3x+4x+6+13-1+12-17-4-10=360

19x-1=360

19x=360+1

19x=361

x=361/19

x=19

Putting the value of x in all the angles and we will find the following:

2x+6=2*19+6=44

x+13=19+13=32

2x-1=2*19-1=37

2x+12=2*19+12=50

2x-17=2*19-17=21

3x-4=3*19-4=51

3x-10=3*19-10=47

4x=4*19=76

Hence among all the exterior angles the smallest angle is 21°.

Learn more about angles at brainly.com/question/25716982

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Step-by-step explanation:

We are given that DE

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\frac{dy}{dx}=16+3xy+24x+2y

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