All categories

3 years ago

A rectangle measures 24cm by7cm. What is it's area?

Mathematics

2 answers:

solmaris [256]3 years ago

8 0

The area is 168 cm.

Alenkinab [10]3 years ago

5 0

168 is the answer to find the area

You might be interested in

4/5(2x+5)−4=1 x = 1 1/4 x = 1 2/5 x = 5/8 x = 3 1/5

tia_tia [17]

The answer is x=5/8. The reason for this is when you divide it equal 0.625 then when you multiply that by 2 it equals 1.25. After you do that you add 5 which is 6.25. Now we divide 4/5 which is 0.8. Now, we multiply 6.25x0.8=5. 5-4=1. Therefore your answer is 5/8. Hope this helps :)

5 0

3 years ago

If f(x)= -5 -7x, find f(-2)

swat32

Answer:

Given f(-2)

= -5 -7(-2)

= -5+14

= 9

Thus f(-2) of f(x)= 5-7x is 9

4 0

3 years ago

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0

3 years ago

How do I solve equations with a variable to the power of something (give steps please)

lozanna [386]

Answer:

Step-by-step explanation:

Factoring will reveal the solution. So we divide the equation by the greatest common factor of the terms and use that factor as the coefficient. In this case the greatest common factor is just x.

2x^2+5x

x(2x+5) so the equation will equal zero when either of those expressions is zero because zero times anything is zero. x=0 and x=-5/2

5 0

3 years ago

Read 2 more answers

Is -38/9 rational or irrational

aleksley [76]

Answer:

yes

Step-by-step explanation:

6 0

3 years ago