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sergiy2304 [10]
3 years ago
6

ANYONE PLEASE HELP ASAP!!!

Mathematics
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

2. B

3.B

4.C

6A. 6

6B. 12

6C. 19.6

6D. 18.75

6E. I cant see

6F. I cant see

Step-by-step explanation:

2. 1/4*40=10

3. type the choice into the calculator

4. 2/5 of 30 or 2/5*30=12

6. A-F type into the calculator

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Factor by grouping <br> 3x^2-11x+10
Burka [1]

Answer: (x - 2)(3x - 5)

Step-by-step explanation:

I'm using the berry method to factor, so first, I multiply 3 times 10 to get 30. Now I have to figure out what two numbers, when multiplied together, yield 30 and when are added together, give me -11. Those two numbers are -6 and -5. The equation now becomes (3x -6)(3x -5). Reducing the first binomial: (3x - 6)/3 = (x - 2)

the solution is (x - 2)(3x - 5), and we can check this by multiplying it out, which gives us our starting number, meaning it's correct.

7 0
3 years ago
Given that sin(x)=7/11, find cos(90-x). A. 4/11 B. 7/11 C. 11/7 D. 11/4
Contact [7]
Based on the given equation above, get the value of x first so that this value can be substituted to the second equation. Value of x can be obtained by taking the arc sin of 7/11 which gives an answer of 39.52 degrees. Substituting this value to the second equation cos (90-39.52) gives an answer equals to 7/11
5 0
4 years ago
PLEASE ANSWER AS SOON AS POSSIBLE WILL GIVE "Brainliest" TO THE FIRST CORRECT PERSON!!!
saw5 [17]

Answer: x=18 ; y=6\sqrt{3}

Step-by-step explanation:

You can write two expressions that are in terms of 'x' and 'y'. This is a right triangle, so Pythagorean's theorem can be used. We can also use the angle to find the sine of 30 degrees.

<u>Pythagorean's Theorem:</u>

The values 'a' and 'b' are the two shorter sides of the triangle, while the value 'c' is the longest side of the triangle; the hypotenuse.

a^2+b^2=c^2

x^2+y^2=(12\sqrt{3} )^2

x^2+y^2=12^2*\sqrt{3} ^2=432

<u>Sine of the Angle:</u>

Sine is defined to be the opposite side divided by the hypotenuse. Let's take the sine of 30 degrees:

sin(\alpha )=opposite/hypotenuse

sin(30)=y/12\sqrt{3}

\frac{1}{2} =y/12\sqrt{3}

y=6\sqrt{3}

Plug this value of 'y' into the first expression derived from Pythagorean's theorem:

x^2+y^2=432

x^2+(6\sqrt{3} )^2=432

x^2+108=432

x^2=432-108=324

x=\sqrt{324}

x=18

Use this value of 'x' to solve for 'y' in the expression from Pythagorean's theorem:

(\sqrt{324})^2+y^2=432

324+y^2=432

y^2=432-324=108

y=\sqrt{108}

y=\sqrt{36*3}

y=6\sqrt{3}

7 0
2 years ago
Which relation is not a function?
Mandarinka [93]

Answer:

c is not a fuction

Step-by-step explanation:

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3 years ago
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Which of these numbers is the greatest? A. 3,213,213 B. 7.8 x 10 C. 6.3 x 10 D. 11,014,114
vichka [17]

Answer:

B


Step-by-step explanation:


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3 years ago
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