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german
3 years ago
13

A ball is dropped from 45 feet above the ground. With each bounce, its max height is 80% of its previous height. What is the bal

l's height at the 14th step of progression? (Round to the nearest hundredths)
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
3 0

Answer: 1.98 ft

Step-by-step explanation: 45(.8)^14

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Your subtotal at the store was $72.29. You have a 40% off coupon. If the sales tax rate is 9.5%, what is the total price for you
ale4655 [162]

$47.50

Step-by-step explanation:

Before tax proce is $72.29

sales tax is 9.5%= $6.87

$72.29+$6.87=$79.16

40% off of $79.16=$47.50

8 0
3 years ago
(9x^4-3x^3+4x^2+5x+7) + (11x^4-4x^2-11x-9)
icang [17]

Answer:

20x^4 - 3x^3 - 6x - 2

5 0
3 years ago
Volume
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Answer:

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6 0
3 years ago
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An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
natita [175]

Answer:

Step-by-step explanation:

Given that:

Population Mean = 7.1

sample size = 24

Sample mean = 7.3

Standard deviation = 1.0

Level of significance = 0.025

The null hypothesis:

H_o: \mu = 7.1

The alternative hypothesis:

H_a: \mu > 7.1

This test is right-tailed.

degree \ of \  freedom=  n - 1 \\ \\ degree \  of \  freedom  =  24 - 1 \\ \\ degree \ of \  freedom   = 23

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test t_c = 2.069

The test statistics can be computed as:

t = \dfrac{ \hat X - \mu_o}{\dfrac{s}{\sqrt{n}}}

t = \dfrac{ 7.3-7.1}{\dfrac{1}{\sqrt{24}}}

t = \dfrac{0.2}{0.204}

t = 0.980

Decision rule:

Since the calculated value of t is lesser than, i.e t = 0.980 < t_c = 2.069, then we do not reject the null hypothesis.

Conclusion:

We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.

6 0
3 years ago
Remember to check for extraneous solutions
larisa86 [58]

Domain:v\neq0\\\\\dfrac{2}{v}+\dfrac{2}{3}=\dfrac{v-6}{3v}\\\\\dfrac{2\cdot3}{v\cdot3}+\dfrac{2\cdot v}{3\cdot v}=\dfrac{v-6}{3v}\\\\\dfrac{6}{3v}+\dfrac{2v}{3v}=\dfrac{v-6}{3v}\\\\\dfrac{6+2v}{3v}=\dfrac{v-6}{3v}\iff6+2v=v-6\qquad\text{subtract 6 from both sides}\\\\2v=v-12\qquad\text{subtract v from both sides}\\\\\boxed{v=-12}\to\boxed{A.}

3 0
3 years ago
Read 2 more answers
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