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Verizon [17]
3 years ago
13

An aquarium has the dimensions shown in the net below. What is the surface area of the aquarium?

Mathematics
2 answers:
marusya05 [52]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Nadya [2.5K]3 years ago
3 0

Answer:

D. 57 Square feet

Step-by-step explanation:

So first you do 4.5x2=9.0 then you times that by 2 so 9.0x2= <em>18</em>

Next, you do 4.5x3= 13.5 then you times that by 2 so 13.5x2=<em> 27</em>

Lastly, you do 2x3 on one side and 2x3 on the other side. For both of those you get 6, so you do 6+6 and you get <em>12</em>

Finally you do

18+27+12=57

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Write an equation in point-slope form for the line through the given point with
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Answer:

Here you go.

Step-by-step explanation:

Hope this helps you!

5 0
3 years ago
How I do this someone ples help I need help with 25 and 27.
marta [7]

Number 15 is no solution.

Number 27 is that x has to be between -2 or 2.

This could be explained as -2≤x≤2

8 0
3 years ago
What is the relative maximum of the function?
Stels [109]

Answer:

(1, 4)

Ste-step explanation:

The relative max of this function is read directly from the graph:  4. This value of y occurs when x = 1.

6 0
3 years ago
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The graphs below have the same shape what is the equation of the red graph
Lisa [10]
Well , I think it’s c
3 0
3 years ago
A player tosses a die 6 times.If gets a number 6 Atleast two times he wins 2 dollars ,otherwise he looses 1 dollar.. Find the ex
swat32

Answer:

E(x)=-0.2101

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x_1*p(x_1)+x_2*p(x_2)

Where x_1 and x_2 are the values that the variable can take and p(x_1) and p(x_2) are their respective probabilities.

So, a player can win 2 dollars or looses 1 dollar, it means that x_1 is equal to 2 and x_2 is equal to -1.

Then, we need to calculated the probability that the player win 2 dollars and the probability that the player loses 1 dollar.

If there are n identical and independent events with a probability p of success and a probability (1-p) of fail, the probability that a events from the n are success are equal to:

P(a)=nCa*p^a*(1-p)^{n-a}

Where nCa=\frac{n!}{a!(n-a)!}

So, in this case, n is number of times that the player tosses a die and p is the probability to get a 6. n is equal to 6 and p is equal to 1/6.

Therefore, the probability  p(x_1) that a player get at least two times number 6, is calculated as:

p(x_1)=P(x\geq2)=1-P(0)-P(1) \\\\P(0) =6C0*(1/6)^{0}*(5/6)^{6}=0.3349\\P(1)=6C1*(1/6)^{1}*(5/6)^{5}=0.4018\\\\p(x_1)=1-0.3349-0.4018\\p(x_1)=0.2633

On the other hand, the probability p(x_2) that a player don't get  at least two times number 6, is calculated as:

p(x_2)=1-p(x_1)=1-0.2633=0.7367

Finally, the expected value of the amount that the player wins is:

E(x)=x_1*p(x_1)+x_2*p(x_2)\\E(x)=2*(0.2633)+ (-1)*0.7367\\E(x)=-0.2101

It means that he can expect to loses 0.2101 dollars.

3 0
3 years ago
Read 2 more answers
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