To solve this, you must rearrange the variables in the given equation. Since we are looking for h, we want the equation to be h = something. You must divide both sides by 1/3 lw. When dividing like this, you must use the KCF (Keep, Change, Flip) method. Keep the first part (v), change the sign from division to multiplication, and flip the fraction. This means that the fraction becomes 3/1 lw. When that is multiplied by v, it makes the equation h = 3v/lw. That is your final answer -> h = 3v/lw.
Answer:
46.375
Step-by-step explanation:
Given information:

where, 0 ≤ x ≤ 3.
We need to divde the interval [0,3] in 6 equal parts.
The length of each sub interval is

Right end points are 0.5, 1, 1.5, 2, 2.5, 3.
The value function on each right end point are






Riemann sum:

![Sum=[f(0.5)+f(1)+f(1.5)+f(2)+f(2.5)+f(3)]\times 0.5](https://tex.z-dn.net/?f=Sum%3D%5Bf%280.5%29%2Bf%281%29%2Bf%281.5%29%2Bf%282%29%2Bf%282.5%29%2Bf%283%29%5D%5Ctimes%200.5)
![Sum=[0.25+3+8.25+16+26.25+39]\times 0.5](https://tex.z-dn.net/?f=Sum%3D%5B0.25%2B3%2B8.25%2B16%2B26.25%2B39%5D%5Ctimes%200.5)


Therefore, the Riemann sum with n = 6 is 46.375.
32x+64 = 160
32x = 96
x = 3
Total blocks = 35+47+22+21 = 125
Sum of red blocks and green blocks = 47+35 = 82
So the probability = 82/125 = 0.656