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3 years ago

Tan^-1[-squareroot3/3] what is the degree

Mathematics

2 answers:

lozanna [386]3 years ago

7 0

Answer:

π/6

Step-by-step explanation:

if tan(pi/16) = squareroot(3)/3

then tan^-1(squareroot(3)/3) = pi/6

Reika [66]3 years ago

3 0

Answer:

150˚ or 330˚

Step-by-step explanation:

It is easier to use the calculator, but you can use the unit circle too.

Calculator:

Plug in the equation without the negative, and you get 30˚ which is your reference angle. But since tangent is negative, the angle is in either the second quadrant, or the fourth (because tangent is negative in these quadrants). Now using your reference angle, you can find the answer.

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Read 2 more answers

PLEASE HELP!!!!!!!! (ALGEBRA II)

qwelly [4]

Answer:

-4 4 4.5 8 20.5 32

Step-by-step explanation:

f $\circ$ g(x) = f(g(x))

Given, f(x) = 2x²

and g(x) = x - 2

Now f(g(x)) = f(x - 2) = 2(x - 2)²

We know that (a - b)² = a² - b² + 2ab

Using this we expand f(g(x)). We get:

f(g(x)) = 2{x² - 4x + 4}

Similarly, g(f(x)) = g(2x²) = 2x² - 2

Now, f(g(-2)) = 2[(-2)² - 4(-2) + 4] = 2(16) = 32.

Also, g(f(-2)) = 2[(-2)² - 2] = 2(2) = 4.

f(g(3.5)) = 2{(3.5)² -4(3.5) + 4} = 2[12.25 - 14 + 4] = 2(2.25) = 4.5.

g(f(3.5)) = 2{(3.5)² -2} = 2{12.25 - 2} = 2(10.25) = 20.5.

f(g(0)) = 2{0 - 4(0) + 4} = 2(4) = 8.

g(f(0)) = 2{0 - 2} = 2(-2) = -4.

Arranging them in ascending order, we get:

-4 4 4.5 8 20.5 32 would be the sequence.

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3 years ago